3(x^2+2x)-2x^2=16

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Solution for 3(x^2+2x)-2x^2=16 equation:


Simplifying
3(x2 + 2x) + -2x2 = 16

Reorder the terms:
3(2x + x2) + -2x2 = 16
(2x * 3 + x2 * 3) + -2x2 = 16
(6x + 3x2) + -2x2 = 16

Combine like terms: 3x2 + -2x2 = 1x2
6x + 1x2 = 16

Solving
6x + 1x2 = 16

Solving for variable 'x'.

Reorder the terms:
-16 + 6x + 1x2 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + 6x + 1x2 = 0

Factor a trinomial.
(-8 + -1x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-8 + -1x)' equal to zero and attempt to solve: Simplifying -8 + -1x = 0 Solving -8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1x = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1x = 0 + 8 -1x = 0 + 8 Combine like terms: 0 + 8 = 8 -1x = 8 Divide each side by '-1'. x = -8 Simplifying x = -8

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-8, 2}

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